作　　者： ; ; ; ;

机构地区： 清华大学环境学院

出　　处： 《环境科学》 2007年第7期1460-1465,共6页

摘　　要： 催化剂Ru/ZrO2-CeO2催化湿式氧化苯酚的过程表明,Ru/ZrO2-CeO2可以显著提高COD和苯酚去除效果,当反应温度为170℃,压力为3 MPa,反应120 min后,COD和苯酚的去除率分别达到了99%和100%.试验还考察了不同反应条件对苯酚溶液COD去除的影响,并获得了最优的反应条件:温度为170℃,压力为3 MPa,催化剂的投加量为5 g/L,搅拌速度为500 r/min.通过对中间产物的分析,本研究提出了催化湿式氧化苯酚的简单路径图,认为苯酚首先被氧化成小分子有机酸,接着小分子有机酸被氧化成二氧化碳和水.前一个过程是快速反应,后一个过程中的乙酸氧化是慢速过程,需要在高温下才能完成.乙酸的氧化主要是自由基攻击α碳上的C—H键,先生成甲酸,并最终生成二氧化碳和水. Wet air oxidation of phenol with Ru/ZrO2-CeO2 was systematically investigated and results showed that Ru/ZrO2-CeO2 could significantly increase the removal of COD and phenol. At the reaction temperature of 170℃ and pressure of 3MPa, about 99% COD and 100% phenol was removed respectively after 120min. The optimal conditions were： reaction temperature, 170℃ ; reaction pressure, 3 MPa; catalyst dosage, 5 g/L; agitator speed, 500 drain. By analyzing intermediates, a simplified scheme of phenol oxidation was brought out. It includes two main steps. The first step is the production of organic acids, which is fast. The second step is the oxidation of organic acid, in which the oxidation of acetic acid is slow. Complete oxidation of acetic acid needs high temperature at which the radicals assault the C--H bond of α carbon and acetic acid is oxidized into carbon dioxide and water through formic acid.

关 键 词： 催化湿式氧化 苯酚 催化剂

领　　域： [环境科学与工程]